Read an integer from the screen and display the int in binary format;. If less than zero program ends. Mov ecx,32; for loop we set ecx to 32; ATTENTION we not. Probably would have been better to test your asm before posting. I guess 'decimal to binary', but the prompt says 'Enter binary value'. Program that will read a binary number and print it on the next line in decimal form using DIV instruction and OUTDEC procedure. Program that prompts the user to enter an array of size 10 and display it. Comment should be atleast 30 Characters. Please put code inside Code your code /Code.
Write a Assembly program for ASCII-Binary conversion with proper output . First of all do ASCII-Gray conversion by Dividing the ASCII number by 2 until the quotient is 0 .
Algorithm for ASCII-Binary conversion
Step I : Get the number whose binary code equivalent is to be found. Step II : Initialize count in CL = 08 H Step III : Divide the number by 2 i.e. shift the number by 1 it to the left. Step III : Display the bit shifted in carry. Step IV : Decrement count Step V : Check if count =0 ? Step VI : If yes go to step VII else go to step III. Step VII : Stop.
Program Code for ASCII-Binary conversion
How to Run this Program For Running this program you should have installed Tasm on you computer . If you have not installed Tasm yet please install from Here .
Result : 0000 1010
Hey guys, first, i wanna say sorry if i'm not making any effort on doing my job here, but im really new to assembly language, i just started like a month ago without any good source.
I got a problem here, i was asked to make a program which a user inputs a decimal value, and can convert the decimal value to hexa, octal and binary.
I already have the codes for each.
Predefined variables
Deci to Hexa
Deci to Octa
Deci to Bin
Don't mind the pre-declared variables because, this are just parts from my program. Wherein, this three are parts of one menu option.
The question is, whenver I put a 'TRY/AGAIN' function(asks user if y/n, if yes, 'jumps' back to this menu, if n, goes back to the very first menu), the value that the hexa, octal, and binary stacks.
SCENARIO: [1]Deci to Hex [2]Deci to Octal [3]Deci to Binary
user inputs 1(for hexadecimal conversion) user inputs 10(decimal) program displays 000A(which is correct) program asks if user wants to try again user inputs y goes back to the same menu
user inputs 3(for binary conversion) user inputs 10(decimal) program displays 00001010(which is correct) program asks if user wants to try again user inputs y goes back to the same menu
user inputs 1(for hexadecimal conversion) user inputs 10(decimal) program displays 030(which is correct) program asks if user wants to try again user exits program
And the same with octal, but in hexadecimal, it outputs 0024.
Any help would be appreciated, i'll try to cope up but to remind you, i just started studying assembly last month.
EDIT: Included the pre-defined variables.
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commentLatest Postby NotNull
Each digit is a multiple of a power of ten. the 4th digit of 9,321 is 9*10^3. Sum each of these multiples of powers of ten (the base) and you'll have the binary equivalent of the value.
If the digits were entered as ASCII subtract 30H (48d) to turn it into an unpacked BCD: 01, 02, 03, 04, 07...
After converting it into an unsigned binary value it is pretty simple to turn it then into hexadecimal and octal being that base 16 and 8 are compact representations of binary.